Question

In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.
What is the probability of getting 1brown and 2 orange M&M's if 3 are taken at a time?
I need help working this problem out!!! please help :)

Answer 1

I think there is a certain formula you have to do!

Answer 2

1/228?

Answer 3

0.00000128

Answer 4

Can you show me how to work it out ?

Answer 5

1 brown and 2 orange M&M's if 3 are taken at a time?
P(1 brown and 2 orange) = [P(1 brown) + P(2 orange)]/20C3
=[P(1 brown)*P(2 orange|1 brown)]/ 20C3
=[(5/20)*2C2/19C2]/20C3
=[(1/4)*(1/171)]/1140
=[0.001462]/1140
=0.00000128

Answer 6

its on this website

Answer 7

That's wrong!

Answer 8

Alright can you show me the correct way?

Answer 9

yeah, that should be
P(1B and 2 O's) = (5C1 * 2C2)/20C3

Answer 10

P(1B and 2 O's) = (5C1 * 2C2)/20C3
= [5!/(5-1)!1! * 2!/(2-2)2!]/(20!/(20-3)!3!)
= [5!/4!1! * 2!/0!2!]/(20!/17!3!)
=(5 * 1)1140
= 5/1140
= 1/228

Answer 11

typo, in the 3rd step
=(5 * 1)/1140

Answer 12

do u have choices as the answer, @Rea731 ?

Answer 13

yes I do and that is the right answer @RadEn

Answer 14

THANKS FOR THE HELP I AM PRETTY SURE I HAVE MORE MATH PROBLEMS TO COME!

Answer 15

you're welcome
if i can, i'll help :)