Mathematics
13 Online
OpenStudy (anonymous):
Can you check my answers? :)
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OpenStudy (anonymous):
\[\sqrt{72}\]
my answer is
\[6\sqrt{2}\]
OpenStudy (mertsj):
That is correct. Good job!!
OpenStudy (anonymous):
can you check some more? :)
OpenStudy (anonymous):
\[\sqrt{49a^8}\]
my answer
\[a \sqrt{24.5}\]
OpenStudy (mertsj):
What is
\[\sqrt{36}\]
and why is it what it is?
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OpenStudy (anonymous):
6, because 6*6=36
OpenStudy (mertsj):
So what is
\[\sqrt{49}\]
OpenStudy (anonymous):
7
OpenStudy (mertsj):
Now refer to your previous problem
OpenStudy (anonymous):
ahh, so 7a^8 is the answer ?
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OpenStudy (mertsj):
\[a^4(a^4)=a^8\]
OpenStudy (mertsj):
\[\sqrt{49a^8}=7a^4\]
OpenStudy (anonymous):
thats what i thought because you could simplify 8 so that would be 4, am i correct? :)
OpenStudy (mertsj):
Not really.
OpenStudy (anonymous):
ah im confused. but 7a^4 is the answer?
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OpenStudy (mertsj):
Yes that is the answer but the reason is:
OpenStudy (mertsj):
\[a^m(a^n)=a ^{m+n}\]
OpenStudy (mertsj):
So
\[a^8=a^4(a^4)\]
so
\[\sqrt{a^8}=a^4`since`(a^4)^2=a^8\]
OpenStudy (anonymous):
oh now im kinda getting it :)
can you check 2 more?
OpenStudy (mertsj):
yes
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OpenStudy (anonymous):
\[2 \sqrt{10} * 3 \sqrt{12} \]
My answer
\[6 \sqrt{120}\]
OpenStudy (mertsj):
But now you have to simplify sqrt(120)
OpenStudy (anonymous):
30
OpenStudy (mertsj):
\[\sqrt{120}=\sqrt{4(30)}=2\sqrt{30}\]
OpenStudy (anonymous):
is it either:
\[12 \sqrt{30}\]
or:
\[12 \sqrt{60}\]
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OpenStudy (mertsj):
So
\[6\sqrt{120}=6(2\sqrt{30})=12\sqrt{30}\]
OpenStudy (anonymous):
Yay! :)
next,
\[\sqrt{14q} * 2 \sqrt{4q}\]
my answer
\[4 \sqrt{14q^2} \]