Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Can you check my answers? :)

OpenStudy (anonymous):

\[\sqrt{72}\] my answer is \[6\sqrt{2}\]

OpenStudy (mertsj):

That is correct. Good job!!

OpenStudy (anonymous):

can you check some more? :)

OpenStudy (anonymous):

\[\sqrt{49a^8}\] my answer \[a \sqrt{24.5}\]

OpenStudy (mertsj):

What is \[\sqrt{36}\] and why is it what it is?

OpenStudy (anonymous):

6, because 6*6=36

OpenStudy (mertsj):

So what is \[\sqrt{49}\]

OpenStudy (anonymous):

7

OpenStudy (mertsj):

Now refer to your previous problem

OpenStudy (anonymous):

ahh, so 7a^8 is the answer ?

OpenStudy (mertsj):

\[a^4(a^4)=a^8\]

OpenStudy (mertsj):

\[\sqrt{49a^8}=7a^4\]

OpenStudy (anonymous):

thats what i thought because you could simplify 8 so that would be 4, am i correct? :)

OpenStudy (mertsj):

Not really.

OpenStudy (anonymous):

ah im confused. but 7a^4 is the answer?

OpenStudy (mertsj):

Yes that is the answer but the reason is:

OpenStudy (mertsj):

\[a^m(a^n)=a ^{m+n}\]

OpenStudy (mertsj):

So \[a^8=a^4(a^4)\] so \[\sqrt{a^8}=a^4`since`(a^4)^2=a^8\]

OpenStudy (anonymous):

oh now im kinda getting it :) can you check 2 more?

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

\[2 \sqrt{10} * 3 \sqrt{12} \] My answer \[6 \sqrt{120}\]

OpenStudy (mertsj):

But now you have to simplify sqrt(120)

OpenStudy (anonymous):

30

OpenStudy (mertsj):

\[\sqrt{120}=\sqrt{4(30)}=2\sqrt{30}\]

OpenStudy (anonymous):

is it either: \[12 \sqrt{30}\] or: \[12 \sqrt{60}\]

OpenStudy (mertsj):

So \[6\sqrt{120}=6(2\sqrt{30})=12\sqrt{30}\]

OpenStudy (anonymous):

Yay! :) next, \[\sqrt{14q} * 2 \sqrt{4q}\] my answer \[4 \sqrt{14q^2} \]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!