Question

(1)how many grams of NaCl are needed to prepare 1000g of 0.9% saline solution?
(2)what is the% by mass of a solution that contains 50 grams of salt dissolved in 200 grams of solution? what is the concentration in ppm?

Answer 1

1000 g x 0.9 % = ?

Answer 2

what is the% by mass of a solution that contains 50 grams of salt dissolved in 200 grams of solution?


200 g + 50 g = 250 g

50g/250 g x100 %=

Answer 3

900

Answer 4

500

Answer 5

lol nope

Answer 6

why not?

Answer 7

0.9 % = 0.009

Answer 8

can you explain me please?

Answer 9

1000 g x 0.9 % = 1000g x 0.9/100 =

Answer 10

1000*0.9=900

Answer 11

it's 0.9% percent
means per hunderd
so you have to divide it by 100
900/100 = 9
you would need 9 gram NaCl to make a 1000g 0.9% salt solution

Answer 12

1000*0.9/100=9

Answer 13

yes :)

Answer 14

I think I can't pass chemistry class. I have a hard time to doing this type of math

Answer 15

It's actually very easy
1000g = 100%
so 900g = 90%
90g = 9%
9g = 0.9%

Answer 16

If you think like this it's a lot easier

Answer 17

Thanks for helping me.

Answer 18

You need help with the second question?

Answer 19

I got some idea now

Answer 20

i will try to do by myself if i can't understand i will back

Answer 21

hint: 50 grams dissolved in 200g is the same as 25g in 100g
its easier to calculate with 100g as you can take that 100%

Answer 22

thank you i will concentrate