Question

simplify the expression.

Answer 1

\[\sqrt{3} + 4\sqrt{3}\]

Answer 2

simple - apply distributive property

\[1*\sqrt{3}+4*\sqrt{3}=(1+4)\sqrt{3}=5\sqrt{3}\]

Answer 3

\[2\sqrt{6} + 3\sqrt{96}\]

Answer 4

ok ill guide you...
first factorise 96 under the root sign and see which factors form pairs

Answer 5

3*32=96

Answer 6

factorise completely----Prime Factorisation

Answer 7

6?

Answer 8

no
96 = 2*2*2*2*2*3

Answer 9

Now see what pairs can you form ans write as square (^2)

Answer 10

????

Answer 11

this is not prime factorisation !!

Prime Factorisation of 96 = 2*2*2*2*2*3=2^2 *2^2 * 6

so root(96) = root(2^2 *2^2 * 6) = 2*2*root(6)

Answer 12

3 x 2 x 2 x 8

Answer 13

3 x 2 x 2 x 2 x 4

Answer 14

3 x 2 x 2 x 2 x 2 x 2

Answer 15

\[2\sqrt{6}+3\sqrt{96}=2\sqrt{6}+3\sqrt{2*2*2*2*2*3}=2\sqrt{6}+3\sqrt{2^{2}*2^{2}*6}\]

Answer 16

\[5\sqrt{96}\]

Answer 17

\[=2\sqrt{6}+3*2*2*\sqrt{6}=2\sqrt{6}+12\sqrt{6}=(2+12)\sqrt{6}=14\]

Answer 18

\[14\sqrt{96}\]

Answer 19

\[=14\sqrt{6}\]