Question

Solve the proportion.

Answer 1

\[\frac{ 4 }{ x } = \frac{ \sqrt{11 } - 1}{ 3 }\]

Answer 2

\[\large \frac{ 4 }{ x } = \frac{ \sqrt{11 } - 1}{ 3 }\]


\[\large 4*3 = x(\sqrt{11 } - 1)\]


\[\large 12 = x(\sqrt{11 } - 1)\]


\[\large \frac{12}{\sqrt{11 } - 1} = x\]


\[\large x = \frac{12}{\sqrt{11 } - 1}\]


I'll let you rationalize the denominator

Answer 3

\[\frac{ 5 }{ 6 }\sqrt{11}-\frac{ 6 }{ 5}\] ???

Answer 4

@jim_thompson5910

Answer 5

oh i messed up it should be 5/6 on the last fraction

Answer 6

\[\large x = \frac{12}{\sqrt{11 } - 1}\]

\[\large x = \frac{12(\sqrt{11 } + 1)}{(\sqrt{11 } - 1)(\sqrt{11 } + 1)}\]

\[\large x = \frac{12\sqrt{11 } + 12}{(\sqrt{11 })^2 - 1^2}\]

\[\large x = \frac{12\sqrt{11 } + 12}{11 - 1}\]

\[\large x = \frac{12\sqrt{11 } + 12}{10}\]

\[\large x = \frac{2(6\sqrt{11 } + 6)}{10}\]

\[\large x = \frac{6\sqrt{11 } + 6}{5}\]

Answer 7

ok thanks :)

Answer 8

yw