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Mathematics 18 Online
OpenStudy (anonymous):

Prove identity: tanx-1/tanx+1= 1-cotx/1+cotx

OpenStudy (anonymous):

tanx = sinx/cosx Hence tanx-1/tanx+1 = (sinx/cosx)-1/(sinx/cosx)+1 Hence (sinx/cosx)-1/(sinx/cosx)+1 = ((sinx-cosx)/cosx)/((sinx+cosx)/cosx) Can you go from here?

OpenStudy (anonymous):

Just one substitution and you will be there: Just use: \[\tan(x) = \frac{1}{\cot(x)}\]

OpenStudy (anonymous):

^ True. My way is 10x more complicated.

OpenStudy (anonymous):

\(\huge \color{blue}{\textbf {Welcome To Openstudy...}}\)

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