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Mathematics 8 Online
OpenStudy (anonymous):

derivative help!

OpenStudy (anonymous):

Im here.

OpenStudy (anonymous):

\[e ^{1-2x}\]

OpenStudy (anonymous):

Ok so the rule with e is that that g(x)=e^f(x) then g’(x)=f’(x)e^f(x)+C

OpenStudy (anonymous):

f(x)=1-2x f’(x)=-2

OpenStudy (anonymous):

so. . . -2e^1-2x +c?

OpenStudy (anonymous):

Yup.

OpenStudy (anonymous):

ok. got it. you would't happen to know anything about natural logs would you? the problem is the derivative of \[\ln \sqrt{x-1}\]

OpenStudy (anonymous):

g(x)=ln.f(x) g’(x)=f’(x)/f(x)

OpenStudy (anonymous):

i got this. . . .

OpenStudy (anonymous):

\[\frac{ \frac{ 1 }{ 2\sqrt{x-1} }}{ \sqrt{x-1} }\] which doesnt seem right

OpenStudy (anonymous):

Because f(x)=(x-1)^-1/2 f’(x)=-1/2(x-1)^-3/2

OpenStudy (anonymous):

right. . .

OpenStudy (anonymous):

so the answer is -1/2(x-1) how do we get rid of the ^-3/2?

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