Question

how to find the derivative of (x+e^1-x)^1/2

Answer 1

use the chain rule

Answer 2

I did it, but I'm stuck on a step

Answer 3

(1/2) (x + e - x)^(-1/2) * d/dx (of what's inside)

Whats inside is a constant e (since x - x is 0), and derivative of a constant is 0, so you have

0 / 2e => 0 ..
at least I think that is correct.

Answer 4

1/2*(x+e^(1-x))^-1/2 * (1-e^(1-x)), how about this i think this might be correct

Answer 5

yes that is what I have @Jmau

Answer 6

ah - e^(1-x) makes a slight difference yes

Answer 7

how do i simplify it

Answer 8

the only thing you can do is move the (x+e^(1-x))^-1/2 to the bottom and that makes it possitive

Answer 9

the answer is

1-2e^1-x^2 over 2 sqr x=e^1-x^2