The equation h = 7 cos (pi/3 t) models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released. a. Solve the equation for t. b. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth. c. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth.
I have this so far am I right? a. h=7cos[(pi/3)t] h/7=cos[(pi/3)t] arccos(h/7)=πt/3 t=3arccos(h/7)/π b. h=1cm t=3arccos(1/7)/π≈1.36 sec .. h=3cm t=3arccos(3/7)/π≈1.08 sec .. h=5cm t=3arccos(5/7)/π≈0.74 sec
Just find the iverse function to find t
are my answers for a and b right?
yes they are
how do you do that @him1618
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