Question

In the parallelogram AYXZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12. Find the value of x and y.

A. x = 4, y = 6
B. x = 48, y = 28
C. x = 6, y = 28
D. x = 6, y = 4

Answer 1

The diagonals of a parallelogram bisect each other.
Segment AX slices segment ZY in half.
Segment ZY slices segment AX in half.
Hence, ZT = TY and AT = TX.
ZT = TY
2x+12 =6x-12

AT = TX
4y-2 = 14

Answer 2

2x+12 =6x-12
4y-2 = 14
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Solve 4y-2 =14 for y.

Solve 2x + 12 = 6x -12 for x.

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