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OpenStudy (anonymous):
Convert theta=60 degrees to a Cartesian equation.
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OpenStudy (anonymous):
You need a length for this to make any sense
OpenStudy (anonymous):
This is all that is given.
OpenStudy (anonymous):
wait, do you mean rotate whatever you're given by 60 degrees?
OpenStudy (anonymous):
I dont know what there are asking for. This is just really exhausting and confusing. They dont really elaborate on anything.
OpenStudy (anonymous):
guess its just \[x=rcos \theta y=rsin \theta \]
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OpenStudy (anonymous):
x=sqrt.(3y)
OpenStudy (anonymous):
\[x=\sqrt{3y}\]
OpenStudy (anonymous):
is that the given?
Could you type all the that is given for the problem?
OpenStudy (anonymous):
Ill put it in the attachment
OpenStudy (anonymous):
ok that's better
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OpenStudy (anonymous):
OpenStudy (anonymous):
wow that's confusing but i would go with a
OpenStudy (anonymous):
well the 1st one
OpenStudy (anonymous):
what math class is this?
OpenStudy (anonymous):
Pre-Cal
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OpenStudy (anonymous):
its the 2nd option. That is the answer
OpenStudy (anonymous):
\[x=\sqrt{3y}\]
OpenStudy (anonymous):
|dw:1365743877178:dw|
Notice we have two points, \((0,0)\) and \((\frac12,\frac{\sqrt3}2)\)... can you determine a linear equation now?
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