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OpenStudy (anonymous):

Linear algebra question

OpenStudy (anonymous):

OpenStudy (anonymous):

Apparantly, I have to find an orthogonal basis, but that is confusing me.

OpenStudy (anonymous):

Cross product will find the orthogonal basis... But I'm sure in this case (where we are doing linear algebra) they want you to find something like the nullspace... or was it the left nullspace?

OpenStudy (e.mccormick):

I also notice the member of what? The \(a,b\in\)???

OpenStudy (anonymous):

member of the real number I would assume.

OpenStudy (anonymous):

@e.mccormick The \(\mathbb{R}\)s got removed.

OpenStudy (anonymous):

Nullspace is just the solution space. That's not what we are asked.

OpenStudy (anonymous):

I have to use projections afterwards somehow.

OpenStudy (anonymous):

@Dido525 Remember the fundamental theorem of linear algebra? It tells you that row space and column space are same dimension, and about their orthogonality.

OpenStudy (e.mccormick):

Yah, usually reals. But I know one prof that works in Q....

OpenStudy (anonymous):

Then I would just cross w1 and w2 to find another vector in R^3 right?

OpenStudy (anonymous):

That's one way to do it, which works okay in this example... but they probably want you to do that whole \[ A^TAx=b \]thing or something.

OpenStudy (anonymous):

Eww...

OpenStudy (anonymous):

Okay so when I find that third vector, What do I do then?

OpenStudy (anonymous):

Okay so a third vector is (0,0,1) which I got using the cross product.

OpenStudy (anonymous):

Okay so here is what my book is saying: When there is no solution to \[ Ax=b \]Then you can use\[ A^TA\widehat{x}=A^Tb \]And \(\widehat{x}\) is the answer with least error.

OpenStudy (anonymous):

This is probably what they want you to use.

OpenStudy (anonymous):

No... Apparantly I have to use projections somehow...

OpenStudy (e.mccormick):

So finding the minimum projection value?

OpenStudy (anonymous):

Erm...

OpenStudy (e.mccormick):

Would that be least squares analysis on the prthogonal projection distance?

OpenStudy (anonymous):

We DO NOT do least squares approximation in this course.

OpenStudy (anonymous):

Not sure how to project a vector onto a basis other than the method I showed you. I do know how to project a vector onto another vector.

OpenStudy (e.mccormick):

OK. Hmm. No clue then.

OpenStudy (anonymous):

Allright. I guess I will ask my professor. Thanks anyways guys!

OpenStudy (anonymous):

Could you give him a medal too wio?

OpenStudy (e.mccormick):

I am not concerened with medals.

OpenStudy (anonymous):

Fair enough :) .

OpenStudy (anonymous):

Seems that you would just add the projections onto each basis vector.

OpenStudy (e.mccormick):

I find it fun and it forces me to remember things. I have even had to look up a few terms that were not in use when I learned Geometry.... like apothem. I am sure they existed, but they just did not bother with them in ages past.

OpenStudy (anonymous):

Do you know how to project a vector onto another vector?

OpenStudy (anonymous):

Yeah I guess you add them. Tat's what my professor said too but how many times do I add them?

OpenStudy (anonymous):

Yeah I know.

OpenStudy (anonymous):

There are two basis vectors... so you do two projections which are added.

OpenStudy (anonymous):

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