tan theta = tan theta ( 2 + sin theta)
Start by dividing both sides by tan theta
This will give you 1 = 2+sin theta
=> sin theta = -1
oh I feel stupid, thank you!!
hmm apparently that is not right
I need 2 different values and -90 is not one of them...
actually 90 might be I think but I need another value ?!?!
(another solution is tan theta =0)
please show me the working
Can you read this yet? \(tan \theta = tan\theta(2+sin\theta)\)
ye si can
its 3 sin theta btw
sorry I missed that out earlier
oh woops that might be why it is wrong..
ok I got 2 of the right answers now, jus need what tan= ...
Awesome! expand terms \[tan \theta = 2tan\theta + tan\theta sin\theta \] Move everything to the right hand side\[tan \theta-2tan \theta-tan \theta sin\theta=0\] Factor out tan\[tan \theta(1-2-sin\theta)=0 \] From here we can say that either \(tan \theta=0\) or \(-1-sin\theta=0\)
Hope that makes sense!
Ok well 3 sin theta will simply change the final bit to something like \[-1-3sin\theta = 0\]For that solution, so no wozza!
hmm but the answers for tan should b 180 and 360, ...
I have noo Idea why :(
If you look at the graph of tan we can see that it repeats every 180 degrees. So actually when one writes \[tan^{-1}(0)\] it is more accurately equal to \(180n\) where n is any integer. So it could be 0, 180, 360, 540,720 etc. (and the same the other way. It helps to have a look at what the function looks like graphically. http://intmstat.com/trigonometric-graphs/tanx.gif
We are trying to find the points where it intersects the x axis. It is clear to see that there will be infinitely many points. For school question they generally just want you to find a couple between -360<x<360
Does that make sense? (Bit of information overload.)
hmm but we got tan theta= 1 or 3 sin theta when I put in 1 it gave 45 degrees. But the answers are 180 and 360. Wht have I done wrong?
I'm pretty sure we got \[tan\theta = 0 \]if you look up to my answer before.
yes we got 0, 1 and the sin one. How do you know which to use?
Because we had\[tan\theta (-1-3sin\theta)=0\] meaning that either \[tan\theta=0\]OR\[ -1-3sin\theta=0\] I'm not sure where we got tan theta = 1 from ?
becaue usually when x is in brackets you just do +1 and + sin theta
oh I get it now thanks!!!!!!!!!!!!!!!!!!!!! you were great
Alright, good job! Sorry for not being clearer
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