Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

circle question, picture drawn below

OpenStudy (anonymous):

|dw:1365765262591:dw|

OpenStudy (shamim):

make clear ur question plz

OpenStudy (anonymous):

i need to figure out the centre of the secon circle, i have the centre of the first one and its radius, also the circles are congruent so i think thet have the same radiuses

OpenStudy (shamim):

wts the value of ur 2 different circle

OpenStudy (anonymous):

circle 1 has a radius of \[2\sqrt{10}\]as does circle 2, circle 1 has a centre point of (3,1)

OpenStudy (anonymous):

the equation of circle 1 is x^2 + y^2 -6x - 2y- 30=0

OpenStudy (anonymous):

|dw:1365770342495:dw|

OpenStudy (anonymous):

the two triangles are congruent. Use distance formula twice to solve for (x,y) |dw:1365770403973:dw|

OpenStudy (anonymous):

or method 2: \[(x-h)^2+(y-k)^2=(2\sqrt{10})^2\] this circle passes through two points.... so, get two equations and sole for (h,k)

OpenStudy (anonymous):

Method 2:\[ (-3-h)^2+(-1-k)^2=40\\ (3+h)^2+(1+k)^2=40\qquad\text{simplify}\\ (1-h)^2+(7-h)^2=40\qquad\text{simplify} \] solve the two equations

OpenStudy (anonymous):

method 1 will give you the same equations. Method 3: use t-ratios

OpenStudy (anonymous):

Method 3 will be more tedious though

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!