circle question, picture drawn below
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make clear ur question plz
i need to figure out the centre of the secon circle, i have the centre of the first one and its radius, also the circles are congruent so i think thet have the same radiuses
wts the value of ur 2 different circle
circle 1 has a radius of \[2\sqrt{10}\]as does circle 2, circle 1 has a centre point of (3,1)
the equation of circle 1 is x^2 + y^2 -6x - 2y- 30=0
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the two triangles are congruent. Use distance formula twice to solve for (x,y) |dw:1365770403973:dw|
or method 2: \[(x-h)^2+(y-k)^2=(2\sqrt{10})^2\] this circle passes through two points.... so, get two equations and sole for (h,k)
Method 2:\[ (-3-h)^2+(-1-k)^2=40\\ (3+h)^2+(1+k)^2=40\qquad\text{simplify}\\ (1-h)^2+(7-h)^2=40\qquad\text{simplify} \] solve the two equations
method 1 will give you the same equations. Method 3: use t-ratios
Method 3 will be more tedious though
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