Find all values of x for which Σ n=1to ∞( (x-2)/3)^n is a convergent geometric series, then express the sum of the series as a function of x.
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OpenStudy (anonymous):
Looks horrible... :3
OpenStudy (anonymous):
calc 2 baby hahah
OpenStudy (anonymous):
Thankfully, I'm here to watch you :)
OpenStudy (anonymous):
Here, I'll even write it for you
\[\huge \sum_{n=1}^\infty\left(\frac{x-2}3\right)^n \]
OpenStudy (anonymous):
Now, when is a geometric series convergent ^.^
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OpenStudy (anonymous):
infininity over infinity
OpenStudy (anonymous):
?
OpenStudy (anonymous):
No, you misunderstand... I just asked when a geometric series is convergent...?
OpenStudy (anonymous):
If |r| < 1
OpenStudy (anonymous):
That's right :)
Now what is r in this specific series?
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OpenStudy (anonymous):
(x-2)/3?
OpenStudy (anonymous):
Right again :D
So you want
\[\huge \left|\frac{x-2}{3}\right|<1\]Now solve :>
OpenStudy (anonymous):
x<5
OpenStudy (anonymous):
and?
OpenStudy (anonymous):
x>-1
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OpenStudy (anonymous):
Correct :)
So your range for x is just
(-1 , 5)
OpenStudy (anonymous):
now how can i express is at a sum of the series? do i do that a/1-r
OpenStudy (anonymous):
Yeah, and as usual, replace r properly...
\[\huge r = \frac{x-2}{3}\]
OpenStudy (anonymous):
so 1/1-((x-2)/3)
OpenStudy (anonymous):
Yup, and simplify as desired ^.^
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OpenStudy (anonymous):
then what
OpenStudy (anonymous):
simplify it, and I'll tell you what then :)
OpenStudy (anonymous):
3/1-x
OpenStudy (anonymous):
And that's actually it :)
OpenStudy (anonymous):
You have just expressed the sum of the series as a function of x.
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OpenStudy (anonymous):
wow thank you so much you were a huge help :) you know your stuff
OpenStudy (anonymous):
That I do ^_^
OpenStudy (anonymous):
prof or past calc 2 student?
OpenStudy (anonymous):
Uhh.. neither :)
OpenStudy (anonymous):
10th grader, actually ^_^
(You just had to ask :> )
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OpenStudy (anonymous):
no way
OpenStudy (anonymous):
your one smart 10th grader
OpenStudy (anonymous):
Well, I guess 10th grader is more believable than "ageless kid from the second to the right and straight on till morning"
But I am in 10th grade, though :)
OpenStudy (anonymous):
how d you know calc two stuff
OpenStudy (anonymous):
Books. Too much time on my hands :)
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OpenStudy (anonymous):
dang well thanks
OpenStudy (anonymous):
Any time (well, not really :> )
OpenStudy (anonymous):
^^^ this guy
OpenStudy (anonymous):
Cheerio ^.^
OpenStudy (anonymous):
so you were not completely right but i fixed the problem