Question

Can anyone explain how to solve this equation?

Answer 1

\[\frac{ 6t ^{2} - t -1 }{ 3(t ^{2} + 1) } = 2\]

Answer 2

Do you know how to factorize quadratic equation?

Answer 3

Sorry, well there is no need of factorization..

Just cross multiply first..

Can you do this?

Answer 4

yes

Answer 5

Cross Multiplication will be your first step..

So go for it and tell me what you got..

Answer 6

\[6t^2 - t - 1 = 2 (3t ^{2} +1)\]

Answer 7

Is this correct?

Answer 8

Yes this is correct, expand RHS more..

Answer 9

Sorry, net got disconnected..

Answer 10

Can you expand RHS more by multiplying 2 to the brackets..

Answer 11

\[the \right side : 6 x 2t^2 +2

Answer 12

Write the whole equation, not the RHS only..

Answer 13

\[(2t-1) (3t+1) = 6 x 2t ^{2} +2\]

Answer 14

is this correct?

Answer 15

Hey, do not factorize the numerator equation..

\[2 \times 3(t^2 + 1) = ??\]

Solve it completely..

Answer 16

On LHS you are getting :
\[6t^2 - t - 1\]

Keep it as such..

On RHS:
you are getting:
\[6(t^2 + 1) = ??\]
can you expand this RHS part by Distributive property??

Answer 17

\[6t ^{2} + 6\]

Answer 18

like this?

Answer 19

Yep..
good..

So you are left with now:
\[6t^2 - t - 1 = 6t^2 + 6\]

Subtract both the sides by \(t^2\) and tell me what did you get?

Answer 20

Sorry subtract by \(6t^2\)..

Answer 21

does t equal -7?

Answer 22

Good...
Yep..

Answer 23

Thanks a lot!:)

Answer 24

You are welcome dear..