Question

What is the length of BC?

Answer 1

you need to use pythagourus's threorem.

Answer 2

Lets start with a^2+b^2=c^2

Now c is your hypotunous, so c=10
Let b =8

So...

a^2+8^2=10^2

solve for a :)

Answer 3

Hmm @hexagon001 I think your picture is a little off, you have a on there twice.

Answer 4

Oh nevermind *facepalm*

Answer 5

Wait yes your picture is off. @lana.831 use the equation I posted up top to work through it, both sides are not 8

Answer 6

Both sides wouldn't be 8

Answer 7

ahh yes the a by itself is supposed to be a b..oopsy

Answer 8

To help simplify it
a^2+8^2=10^2
a^2+64=100
a^2=36

you should be able to solve for a from there :)

Answer 9

BC = sqrt(100^2-8^2)

Answer 10

6? @edlevin

Answer 11

Yepp. 6 is correct.

Answer 12

Yup :)

Answer 13

Yes. :-)

Answer 14

DRAT!!! My answer was wrong!!!

However, it looks like you knew what I meant, so all's well that ends well... :-)

What I WROTE was: BC = sqrt(100^2-8^2)

What I MEANT was: BC = sqrt(10^2-8^2)

And to explain it, this is because AC (the hypotenuse) is:

AC^2 = (BC^2 + AB^2)

This means that:

BC^2 = AC^2 - AB^2

So the square root of that is what gives you BC.