Can someone help me create a problem that has a binomial which IS a factor of the polynomial being divided?
If 2(3)=6 what is 6/3?
2.
Is 3 a factor of 6?
Yes.
So perhaps we could use that idea and apply it to binomials so we end up with a polynomial that has a binomial factor.
Make up a binomial and post it.
y = 2x + 10
Make up one which is not factorable.
See why you can't get help. I have been trying to help you for more than 2 hours and you have disappeared yet again.
Sorry, I keep forgetting to check back into Openstudy.
A non factorable binomial could be \[v^{2} + 16\]
Make up a second binomial
\[(x - 1)^{2}\]
That is a binomial squared. What is the matter with something simple like x+2 or something?
Okay, x + 2
Multiply your two binomials.
Use the same variable in both. Lose the v and put x
Could you hold on please, I have to make a short phone call?
I'm outta here.
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