Use the Binomial Theorem to find the binomial expansion of the expression. (d+3)^7
@amistre64
might help to determne what the thrm states
huh? o.o
(p+q)^n = \(\Large \sum_{r=0}^{n}\binom{n}{r}~p^nq^{...}\) forgot the q part
you are being asked to apply a thrm, so it would be best to know the thrm. the rest is just filling in the specifics
r+n, and r
\[\Large \sum_{r=0}^{n}\binom{n}{r}~p^{n-r}~q^{r}\]
oh okay.. I'm just stuck on which one is right..d7 + 21d6 + 189d5 + 945d4 + 2835d3 + 5103d2 + 5103d + 2187 or d7 + 7d6 + 21d5 + 35d4 + 35d3 + 20d2 + 7d + 1..
i believe the 21, 35 stuff is if q=1
1 7 21 35 35 21 7 1 is a direct line from pascals triangle, which would represent q=1 in this case
.-. but these are the options i have.. -bit confused-
Ohh ok
and what is the difference between the options? the coeffs of each term. in the setup (p+1)^7 , the coeffs follow pascals triangle: 1 7 21 35 ... notice that your problem has q=3, not q=1. so which one of these options would we choose?
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