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Mathematics 15 Online
OpenStudy (anonymous):

http://prntscr.com/109aiy

OpenStudy (anonymous):

But if A represents P(event A) and similarly for B, you have (1/2 * 1/2 + 1/2 * 1/2)^2 = (1/4 + 1/4)^2 = (1/2)^2 = 1/4 1/2p(A) + 1/2(p(B)) = (1/2*1/2 + 1/2*1/2) = .25 + .25 = .5 For part (b): Roll one of the cubes. The top facing number will be either from {1 5 6} or {2 3 4} - it doesn't matter which. Then you want the other one to have its top face come from the other trio of numbers, so P(success) = 3/6 = 1/2

OpenStudy (anonymous):

i got the part (a) of the answer wrong can you help

jimthompson5910 (jim_thompson5910):

(1/2A + 1/2B)^2 = (1/2A)^2 + 2*(1/2A)*(1/2B) + (1/2B)^2 (1/2A + 1/2B)^2 = (1/4)A^2 + (1/2)AB + (1/4)B^2

OpenStudy (anonymous):

means?

jimthompson5910 (jim_thompson5910):

it means (1/2A + 1/2B)^2 simplifies to (1/4)A^2 + (1/2)AB + (1/4)B^2

jimthompson5910 (jim_thompson5910):

The probability of event A or event B happening is P(A or B) = P(A) + P(B) - P(A and B) P(A or B) = 1/2 + 1/2 - (1/2*1/2) P(A or B) = 1/2 + 1/2 - 1/4 P(A or B) = 3/4

OpenStudy (anonymous):

YOU MEAN to say this will be answer for part a

Directrix (directrix):

@LilySwan Try posting your question in this thread.

OpenStudy (anonymous):

@Directrix

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