The equation h = 7 cos (pi/3 t) models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth.
any idea?
i think i have to find the iverse function to find t can you help?
nd so if h=1 you get t=3/πcos^−1(1/7)
what about the 5?
that is where i get confused...
this the answer of A
A: π/3 cos^−1(h/7)
ok i think i got it thanks ;)
right typo there 3/π
you start at t=0 i believe, so rest position is 7
another screwy question starts at 7, goes down to -7 and then back up to 7 it is never 1 above 7
it is litle bit confuse your exercice but it is like that i am sure
yeah it is confusing, but you really helped thanks!
let continue maybe i can do more for you ^^
more explaination h = A*cos(Bt + C) + D where D is some positive number to have this make sense (and not have negative heights)
actually, D > 7 for this to make complete sense
ok :D?
wait im so confused right now
you can imagine it touching the ground at the lowest point if D = 7
where did D come from?
i answered ;)
imagine that the lowest point if d=7
oh yeah ok i got now! i hadn't read everything you typed
've seen instances where arcsine(y) = {x| sin(x) = y} and sin^(-1) was the actual function but it depends on the book really
i give you medal at least you understand i hope so ^^
yeah thanks! i will give you a medal for explaining throughly! thanks sooo much!
thanks for the medal too! =D
Join our real-time social learning platform and learn together with your friends!