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What does this e term equal to just i, and imaginary number?
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\[\sum_{k=\infty}^{\infty} {e}^{-i 6\pi (k-(\frac{ 1 }{ 12 }))}\]
the term inside the summation is equal to i for some reason
Every term except the one at k=zero has a corresponding term with opposite sign that cancels it. That means the summation is just the one term, which is exp(i pi/2)=i.
Oh right that make senses thanks so much for your help!
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