A simple pendulum with mass m = 1.3 kg and length L = 2.69 m hangs from the ceiling. It is pulled back to an small angle of θ = 11.9° from the vertical and released at t = 0.

What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0?

Question

A simple pendulum with mass m = 1.3 kg and length L = 2.69 m hangs from the ceiling. It is pulled back to an small angle of θ = 11.9° from the vertical and released at t = 0.

What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0?

anonymous · Answer

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anonymous · Answer

$$m *g * \sin \theta = 1.3 * 9.8 * \sin 11.9 = 2.63 N$$

anonymous · Answer

-__- wow im a noob.

anonymous · Answer

thank you

anonymous · Answer

do you know how you would find the maximum sped of the pendulum? @zaphodplaysitsafe

anonymous · Answer

maximum speed can be got from taking the maximum height to which the bob was raised.
so if the height was h,  then for maximum speed(at the bottom most position), all the energy of the pendulum will be kinetic energy.
hence $$1/2 * m * v^2 = m*g*h$$
so we just need to find h in your case.
the angle to which it was raised was theta
hence the height h = $$L*(1 - \cos \theta)$$ where L is the lenght of the pendulum string.

now you can calculate v from this.

anonymous · Answer

Ok, that makes sense. Awesome, I really appreciate it! Thank you

anonymous · Answer

you're welcome