Question

i need to solve

\[\log _{0,7}\log _{2}\frac{ 3+5x }{x ^{2}+3}<\log _{0,7}1\]

Answer 1

@Mertsj

Answer 2

@kausarsalley do you have any tips?

Answer 3

no...but i want to try it out...

Answer 4

@ash2326

Answer 5

@Mertsj

Answer 6

Cant it be written as \[\[\log _{0,7}\log _{2}\frac{ 3+5x }{x ^{2}+3}<\log _{0,7}\log _{2}2\]\]

Answer 7

?

Answer 8

@hartnn

Answer 9

@AravindG

Answer 10

@saifoo.khan

Answer 11

Well, first of all, the log of 1 is 0 so the right side is 0

Answer 12

oh,okay

Answer 13

Is that base 0.7?

Answer 14

yes

Answer 15

it is a loghorhytm in logorhytm

Answer 16

actually, I have made to this logorhytm. the problem is:

\[5^{\log_{0,7}\log_{2}\frac{3+5x}{x^{2}+3}}<1\]

Answer 17

maybe I have done something wrong!

Answer 18

@Mertsj any ideas?

Answer 19

http://www.wolframalpha.com/input/?i=log_%280.7%29%28log_2%28%283%2B5x%29%2F%28x^2%2B3%29%29%3C0

Answer 20

well, let me show how I done, maybe you will find my mistake,okay?