Solve x^2 + 9x = –3. (using quadratic formula)
Do you know the Quadratic Formula?
Rearrange to get it in the form \(ax^2 +bx+c=0\) (shouldn't be too hard) and then use \[x = \frac{-b \pm\sqrt{b^2-4ac}}{2a}\] substituting the values that you find. Hope that helps!
What is the a, b, and c in this equation? @Britt101
to start of the function would be \[x^2+9x+3=0\]
a=1 b=9 c=3
Good, now plug in the a, b, and c into the quadratic formula. @Britt101
Tell us what you get as your final answer or ask any questions if you have any, as needed. @Britt101
Go Luis!
-9+or-(squared) 69/2?
@Comm.Dan
Just if anyone wants to copy this code: [x=\frac{-b \pm \sqrt{b^2-4ac}} {2a}\] Smash in a \ at the beginning
I think you might've subtracted wrong @Britt101
no you're right but its square root
now you have to solve for x when its + and when its -
@galacticwavesXX Are you trying to say that she is right?
im saying she hasn't solved for it completely
Ok. Just wanting to make sure. @galacticwavesXX
no that as far as im suppose to go. I don't have to solve for x.
she has \[\frac{ -9\pm \sqrt{69} }{ 2 }\]
now she has to solve for x which shouldn't be too hard
yeah that what i chose for my answer it dose not ask to go and find x.
@Britt101 Just solve for both of the x's and you will find it easy after you do some practice.
oh ok just making sure!
thanks you guys :) I really glad ya'll both helped :) Thanks.
you welcome anytime!
No problem. Do you have any more questions at this time? @Britt101
@galacticwavesXX What are the solutions of 4x2 – 3x – 5 = 0? is it \[\frac{3 \pm \sqrt{89}} {8} \]
let me do it first see if you got it
okay
yes it is correct
you got it!!:)
Nice job. Do u have any more regular or clarification questions? @Britt101
yeah Solve. 3x2 = 147 x=7 or x=7 & x=-7? I think it's x=7&x=-7
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