A two-day conference is going to be held in a city. The leading newspaper in the city says there is a 10% chance of rain on the first day of the conference and a 40% chance of rain on the second day. If the newspaper’s figures are correct, the chance that it rains in the city during the conference is: at least 0%, but we can’t get a better lower bound with the information given. at least 10% but it might be less than 40%. at least 40%.
If the newspaper’s figures are correct, the chance that it rains in the city during the conference is at most 10%. at most 40%. at most 50%. at most 100%; that’s the best upper bound we can get based on the information given.
Assuming the events 'rains on first day' and 'rains on second day' are independent, the probability of not raining on either day is given by \[P(no\ rain\ either\ day)=(1-0.1)\times (1-0.4)=0.9\times 0.6=0.54\] Therefore \[P(rains\ during\ conference)=1-0.54=0.46\]
can any one post the corect ans for the above question
A two-day conference is going to be held in a city. The leading newspaper in the city says there is a 10% chance of rain on the first day of the conference and a 40% chance of rain on the second day. PROBLEM 6A This Problem is worth 1 Point If the newspaper’s figures are correct, the chance that it rains in the city during the conference is: at least 0%, but we can’t get a better lower bound with the information given. at least 10% but it might be less than 40%. at least 40%.
Hi, 6a) at least 40% it's right answer good luck!
I am with a group of five of my friends. A box contains 8 pieces each of milk chocolate, white chocolate, and dark chocolate. The box is passed around the six of us, with each person taking 4 pieces. Assume that each person chooses at random without replacement from the available pieces. I am the last person to whom the box is passed. Find the chance that I pick 4 dark chocolates.
plsssss ans
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