Question

solve the equation
log(base 6)(x+9)-log(base 36) x=1

Answer 1

try rewriting your statement in forms of the natural log, using the base change law of logarithms.

Answer 2

so what you are saying is changing it to log(base6)(x+9)/log(base36)x =1 ?

Answer 3

well you didn't change anything right there, but you can write log_6(x+9) as:

\[\log_6(x+9)=\frac{ \ln(x+9) }{\ln6 }\]

Answer 4

okay. understand that. so would you do the same with the other one too. so it will look like lnx/ln38

Answer 5

Is that your problem?
\[\log_6(x+9)-\log_{36}x=1\]
Sorry my windows machine loads slow, so I maybe have misinterpreted the brackets in your opening post.

Answer 6

yes

Answer 7

then yes indeed, continue that way. just notice that 36 = 6*6 = 6^2