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OpenStudy (anonymous):
Simplify \[(2^3+4^3)^{-1/9}\]
OpenStudy (anonymous):
okay so lets start from the beginning, what would you do since the exponent is negative?
OpenStudy (anonymous):
Choices are:
a) -2
b)\[8^{-1/3}\]
c)1/2
d)2
OpenStudy (anonymous):
|dw:1365888291094:dw|
OpenStudy (anonymous):
after you turn the exponent into positive, you can work on the inside of the parenthesis and solve 2^3+4^3 which is just 2*2*2+4*4*4
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OpenStudy (anonymous):
so 1/72
OpenStudy (anonymous):
|dw:1365888384018:dw|
OpenStudy (anonymous):
Use this rule for negative exponents.
\[ \left( \frac{ a }{ b } \right)^{-x} = \left( \frac{ b }{ a } \right)^x\] So your question becomes:\[(2^3+4^3)^{-1/9}= \left( \frac{ 1 }{ 2^3+4^3 } \right)^{1/9}=\frac{ 1 }{ (2^3+4^3)^{1/9} }\] Just calculate the answer now. Can you do that? @evy15
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
@evy15 you forgot about the 1/9
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OpenStudy (anonymous):
Ok @evy15 post the answer you get and I'll tell you whether it's correct or not.