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Mathematics 9 Online
OpenStudy (anonymous):

Help

OpenStudy (anonymous):

Simplify \[(2^3+4^3)^{-1/9}\]

OpenStudy (anonymous):

okay so lets start from the beginning, what would you do since the exponent is negative?

OpenStudy (anonymous):

Choices are: a) -2 b)\[8^{-1/3}\] c)1/2 d)2

OpenStudy (anonymous):

|dw:1365888291094:dw|

OpenStudy (anonymous):

after you turn the exponent into positive, you can work on the inside of the parenthesis and solve 2^3+4^3 which is just 2*2*2+4*4*4

OpenStudy (anonymous):

so 1/72

OpenStudy (anonymous):

|dw:1365888384018:dw|

OpenStudy (anonymous):

Use this rule for negative exponents. \[ \left( \frac{ a }{ b } \right)^{-x} = \left( \frac{ b }{ a } \right)^x\] So your question becomes:\[(2^3+4^3)^{-1/9}= \left( \frac{ 1 }{ 2^3+4^3 } \right)^{1/9}=\frac{ 1 }{ (2^3+4^3)^{1/9} }\] Just calculate the answer now. Can you do that? @evy15

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@evy15 you forgot about the 1/9

OpenStudy (anonymous):

Ok @evy15 post the answer you get and I'll tell you whether it's correct or not.

OpenStudy (anonymous):

so do (72)^1/3 and that answer should be over 1

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