Question

simplify completely

Answer 1

ok, what would the first step be @AriPotta do you know? If not, let me know, and i'll get you through it step by step :)

Answer 2

Just factor and cancel

Answer 3

would it be to find the gcf?

Answer 4

@Hero ,let her figure it out :)

Answer 5

@AriPotta , as hero said, first factor the top part

Answer 6

follow hero's advice

Answer 7

ignore the rest of the people

Answer 8

2(x^2 + 10x + 16)?

Answer 9

10 and 16
8+2 and 8x2

Answer 10

so the x^2s would cancel

Answer 11

wait

Answer 12

erg?

Answer 13

no, that's not true. you want to factor the top and the bottom then

Answer 14

by factoring, you will get 2*(x+2)*(x+8) on the top, and (x-10)*(x+8)

Answer 15

do you understand how to get to that step?

Answer 16

i guess ._.

Answer 17

ok, if i asked you to factor \[x ^{2}+8x+16\] how would you do it?

Answer 18

First try factoring the top and bottom and see if anything cancels out.\[\frac{ 2(x^2+10x+16) }{ x^2-2x-80 }=\frac{ 2(x+2)\cancel{(x+8)} }{ (x-10)\cancel{(x+8)} }=\frac{ 2(x+2) }{ (x-10) }\]
@AriPotta

Answer 19

So I first factored out the two. Then I factored the quadratics in the numerator and denominator. Cancelled out x + 8, and the remaining expression is the simplest form it can take. Do you understand?

@AriPotta

Answer 20

ok...thanks