2CH6 + 7O2 --> 4CO2 + 6H2O When I already have the balanced equation, how do I find how many grams of CO2 are produced when 2.00 moles of C2H6 react with sufficient O2? I'm having trouble understanding finding how many grams needed for a reaction with grams/moles of another substance.
2C2H6 + 7O2 --> 4CO2 + 6H2O 2moles of C2H6 produces 4 moles of CO2 n=m/Mr......
It asks how many grams of CO2...
You can calculate the amount of grams if you know the amount of moles. To do this you need the molecular weight of the compound. You will need a periodic table to calculate the molecular weight. First check what the compound is made of. In this case CO2 consists of carbon and oxygen Look on a periodic table and you'll see: 1 mole of carbon weights 12.0107 grams 1 mole of oxygen weights 15.9994 grams You have 1 carbon and 2 oxygen so 12.0107 + (2*15.9994) = 44.0095 gram/mole So 1 mole CO2 weights 44.0095 grams You have 4 mole CO2 so just 4* 44.0095 = 176.0380 gram CO2
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