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OpenStudy (anonymous):
\[5 = \log_{3} ( x^2 + 18)\]
OpenStudy (anonymous):
\[-2 = \log (3x+5)\]
OpenStudy (ash2326):
Raise both sides by power of 3, for the first question
OpenStudy (anonymous):
\[e^x e^{x+1} = 1\]
OpenStudy (anonymous):
why?
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OpenStudy (ash2326):
We know the logarithmic property
\[a^{\log_a b}=b\]
so
\[5 = \log_{3} ( x^2 + 18)\]
raising both sides by power of 3
\[3^5=x^2+18\]
I think you can solve now, can't you ?
@kaylalynn
OpenStudy (anonymous):
why is it 3^5 if we are raising both sides to the power of 3?
OpenStudy (anonymous):
@ash2326
OpenStudy (anonymous):
Because of the log rules we can see from the problem that it is to \[\log_{3} \]
OpenStudy (anonymous):
you have to set \[3^5\]
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OpenStudy (anonymous):
both sides to the power of 3 to cancel out the log on the the right side
OpenStudy (anonymous):
which will leave you with \[243=x^2+18\]
OpenStudy (anonymous):
then solve for x
OpenStudy (anonymous):
Do you understand it now?
OpenStudy (anonymous):
yes!
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OpenStudy (anonymous):
ok as long as you understand there's satisfaction!