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Mathematics
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Use an angle sum identity to verify the identity .
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\[\cos 2\theta =2\cos^2 \theta-1\]
\[\cos(x)=\cos(x+x)=\cos(x)\cos(x)-\sin(x)\sin(x)\] \[=\cos^2(x)-\sin^2(x)\] now replace \(\sin^2(x)\) by \(1-\cos^2(x)\) to get your result
\[\large \cos 2\theta =\cos (\theta +\theta)\] \[\large =\cos \theta \cos \theta -\sin \theta \sin \theta\] \[\large =\cos^2 \theta -\sin^2 \theta\] Using your trig identities: \[\cos^2 \theta +\sin^2 \theta =1\] \[\sin^2 \theta =1-\cos^2 \theta\] \[\large =\cos^2 \theta -(1-\cos^2 \theta)\]
You can finish that last bit off, but make sure you learn your trig identities, double angles until it's printed in your brain.
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