Question

a train is moving 4.82 m/s when it begins to accelerate. after 24.8s it is moving 7.09 m/s. how far did it move in that time? HELP PLZ

Answer 1

So what u do is rearrange the formula from your first question to get Distance=(velocity)*(time) where velocity =(7.09-4.82) and the time is (24.8-0) therefore the
Distance=(7.09-4.82)*(24.8)
Distance=56.296metres

Answer 2

thank u but the answer is wrong :-/ i tried that already before and nothing :(

Answer 3

whats the answer????

Answer 4

i dont know. :/ im still stuck :(

Answer 5

so how do u know if the answer above is wrong?

Answer 6

because i am taking online classes and this is one of the question they have asked me to answer and i put this answer and it came out wrong. :/

Answer 7

oh ok give me some time ill try work out this question and then help u out if that is alright

Answer 8

thanks

Answer 9

u=4.82 m/s
v=7.09 m/s
t=24.8 s
a=?
s=?
v=u+at
7.09=4.82+24.8a
24.8a=7.09-4.82=2.27
a=2.27/24.8
s=ut+1/2at^2
s=4.82*24.8+1/2 *2.27/24.8 *(24.8)^2
s=(4.82)*(24.8)+1/2 *2.27*24.8
s=24.8*(4.82+1.135)
s=24.8*5.955
s=147.684 meters