Question

Verify: 1- sin^2X/1+cosX =CosX

Answer 1

@abb0t Help!

Answer 2

\(\frac{ 1-\sin^2(x) }{ 1+\cos(x) }= \cos(x)\) is that correct?

Answer 3

Combine denominators. You get: \[\frac{ 1+\cos(x) }{ 1+\cos(x) }-\frac{ 1-\sin^2(x) }{ 1+\cos(x) }\]

Answer 4

taking lcm we will get
(1 + cosx - sin^2x)/1 + cos x
now 1 - sin ^2 x is cos^2x
just substitute and u will get the answer

Answer 5

Note: \(1-\sin^2(x)=\cos(x)\)

Answer 6

Can you figure it out from here?

Answer 7

No im lost big time>.< wait so who's right?

Answer 8

Help!D: i dont get this subject at all like at all

Answer 9

no 1 - sin^2x is cos^2x
so the equation becomes
(cos^2x + cosx)/1+cosx
take cosx common from the numerator u will get
cosx(1+cosx)/1+cosx
= cosx thus proved
:D

Answer 10

@dhanamkoilraj where did you get the "+' from on ur numerator?

Answer 11

becoz the numerator is 1 + cosx - sin^2x = cos^2x + cosx

Answer 12

is # 2

Answer 13

yea this is the solution to tat question

Answer 14

This is correct no?

Answer 15

@abb0t @dhanamkoilraj ?

Answer 16

So it this correct?

Answer 17

yea its correct

Answer 18

Thanks for the approval! ^-^

Answer 19

no probs :D

Answer 20

\[CosX \div 1-Sin ^{2}X = SecX\]

Answer 21

again 1- sin^2x is cos^2x
so the equation becomes
cosx/cos^2x
which is equal to 1/cosx
= secx