For 0°≤θ≤360°, how many roots does the equation 3sin^(2)x+2sinx-1=0 have?
let sinx=y
=> 3y^(2)+2y-1=0
y=1/3 or -1
.....
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OpenStudy (raden):
3y^(2) + 2y - 1 = 0
this, can be factored
(3y - 1)(y + 1) = 0
now solve for y
OpenStudy (anonymous):
y=1/3 or -1
OpenStudy (raden):
yup
OpenStudy (anonymous):
sinx=1/3
sinx=-1
OpenStudy (raden):
hmm.. for sin x = 1/3, this is not special angle in trigono. so use ur calculator to get x by take sin^-1
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OpenStudy (anonymous):
After all, you are only asked how many roots, right?
Or are they asking for specifics?
OpenStudy (anonymous):
@RadEn sinx=1/3
x=19.471220634491
@PeterPan i also want to know what're the roots
OpenStudy (anonymous):
Well, in that case, it doesn't look like there's much of a choice but to use calculators :)
OpenStudy (anonymous):
one of them is 19.47
OpenStudy (anonymous):
180-19.47=160.53 <<< is it correct?
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OpenStudy (anonymous):
Way ahead of me :)
OpenStudy (anonymous):
any roots else?
OpenStudy (anonymous):
sin(x) = -1
OpenStudy (anonymous):
270
OpenStudy (anonymous):
Those are all, I suppose. Three roots.
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OpenStudy (anonymous):
okay, thanks
OpenStudy (raden):
agreed ^
OpenStudy (anonymous):
and 0°≤θ≤360°, how many roots does the equation cos^(3)x=cosx have?
OpenStudy (anonymous):
Do the same, but first, rearrange into
cos^3(x) - cos(x) = 0
and let y = cos(x) this time
OpenStudy (anonymous):
y^(3)-y=0
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OpenStudy (anonymous):
Yes... and this can be factored. quite nicely, actually.
OpenStudy (anonymous):
It factors neatly into
y(y - 1)(y + 1)
OpenStudy (anonymous):
So what are the values for y?
OpenStudy (anonymous):
cosx=0
cosx=1
cosx=-1
OpenStudy (anonymous):
That's right. And these are all special, aren't they? ^.^
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OpenStudy (anonymous):
90 , 270, 0, 360, 180
OpenStudy (anonymous):
five??
OpenStudy (anonymous):
five roots...
I find it a bit weird that both 0 and 360 are included, aren't they essentially the same?
But yeah, you said your interval was 0°≤θ≤360°
So you're correct. And yes, five.
OpenStudy (anonymous):
another person also confusing that 0 and 360, i think these two should be included
OpenStudy (anonymous):
It should be safe enough. ^.^
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OpenStudy (anonymous):
For 0°≤θ≤360°, how many roots does the equation 2cos^(2)θ-5sinθ-4=0 have ?
OpenStudy (anonymous):
Leveling up? ^_^
Why did you change cos to sin? That's not allowed :)
OpenStudy (anonymous):
-2sin^(2)θ-5sinθ-2=0
OpenStudy (anonymous):
ohh. okay...
OpenStudy (anonymous):
2cos^(2)θ-5sinθ-4=0
2(1-sin^(2)θ)-5sinθ-4=0
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OpenStudy (anonymous):
Then the answer is zero roots :D
OpenStudy (anonymous):
sinx=-2 or -0.5
OpenStudy (anonymous):
or that... I thought you said imaginary?
OpenStudy (anonymous):
nothing, i press the calculator wrongly
OpenStudy (anonymous):
Okay, so you've worked out that sinx = -2 or sin(x) = -0.5
What's your conclusion? :D
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OpenStudy (anonymous):
i got 150° so far..
OpenStudy (anonymous):
Okay, just had to convince myself :D
150 is good, and there should be one more...
OpenStudy (anonymous):
wait, no.... 150 is not good at all, you need
sin(x) = -0.5
sin(150) = 0.5
OpenStudy (anonymous):
210?
OpenStudy (anonymous):
Yeah, much better :)
And one more.
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OpenStudy (anonymous):
sin^(-1) -2?
OpenStudy (anonymous):
no... uhh
one more value for x which would make
sin(x) = -0.5
NOTE: There is no value for x which would make
sin(x) = -2
sin only ranges from -1 to 1 ^.^
OpenStudy (anonymous):
ohh, yes..
OpenStudy (anonymous):
sinx=-0.5
x=-30
270-(-30)=300 ?
OpenStudy (anonymous):
Most excellent ^.^
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OpenStudy (anonymous):
3 roots?
OpenStudy (anonymous):
Only two :)
OpenStudy (anonymous):
the two values for x which would make sin(x) = -0.5
OpenStudy (anonymous):
ohh yes.
OpenStudy (anonymous):
i understand the concept now :)
thank you very much
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OpenStudy (anonymous):
You're quite welcome ^.^
OpenStudy (anonymous):
how about...
OpenStudy (anonymous):
For 0°≤θ≤360°, how many roots does the equation tanx=2sinx have?