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There are six chairs in a row. Person A picks one of the chairs at random. Then Person B picks a chair at random from the five chairs that remain. Find the chance that they pick chairs that are next to each other.
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tricky.
yes it is
conditioning on whether the chair A picks is on the leftmost or rightmost or not
all modes of picking chairs is : \[\left(\begin{matrix}6 \\ 1\end{matrix}\right)*\left(\begin{matrix}5 \\ 1\end{matrix}\right)\]=30 and all modes of picking chairs are belong is 2*5=10 so probability I think is 1/3
Yes, that's correct :)
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In case you need more than 1 answer: (2/6)*(1/5)+(4/6)*(2/5)=1/3 :)
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