Question

Evaluate the double integral

Answer 1

Evaluate over general region D, where D = {(x,y): 0 <= x <= pi, 0 <= y <= sin(x).

\[\int\limits_{}^{}\int\limits_{D}^{}x dA\]

Answer 2

It's already been laid out it would seem...
\[\Large \iint\limits_D x \ d A=\int\limits_{0}^{\pi}\int\limits_{0}^{\sin(x)}x \ dydx\]

Answer 3

I also had it like that, I got to this:
\[\int\limits_{0}^{\pi}xsinx {dx}\]
\[=\left[ -xcosx+\int\limits_{}^{} cosx dx\right]_{x=0}^{x=\pi}\]
\[=-\pi \cos\pi + \sin\pi + \sin0 = -3.08\]

Answer 4

I see I actually got it right. I forgot to set my calculator on radians.

The aswer is
\[\pi\]