A die is a six-sided figure; each side shows a number of spots; the numbers of spots on the six sides are 1, 2, 3, 4, 5, and 6. Unless the problem says otherwise, you can assume that the die is fair, that is, each face has chance 1/6 of appearing regardless of what has appeared before. 1.A die is rolled three times. Find the chance that the face with 4 spots appears at least once. 2.A die is rolled three times. Find the chance that three different faces appear.
i believe it is 3/18 and 15/18. not sure though.
no its wrong
Do you have answer choices?
no
1. 31/216 2. 5/9
1 is wrong
3/216?
now i dont knw about th 1 one
oops 91/216
1. What is the prob of 4 not appearing at all ?
tell me the answer of part 2
If you only want ans. then (1) P = \( 1 - \cfrac{5^3}{6^3}\)
(2) P = \(\cfrac{6*5*4}{6^3}\) = \(\cfrac{20}{36}\)= \(\cfrac{15}{18}\)
yeah its ryt 91/216
Well why do you want only answers ?
i didnt mean that first explain me then tell me how to solve it
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