A die is a six-sided figure; each side shows a number of spots; the numbers of spots on the six sides are 1, 2, 3, 4, 5, and 6. Unless the problem says otherwise, you can assume that the die is fair, that is, each face has chance 1/6 of appearing regardless of what has appeared before.
1.A die is rolled three times. Find the chance that the face with 4 spots appears at least once.
2.A die is rolled three times. Find the chance that three different faces appear.
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OpenStudy (anonymous):
i believe it is 3/18 and 15/18. not sure though.
OpenStudy (anonymous):
no its wrong
OpenStudy (anonymous):
Do you have answer choices?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
1. 31/216
2. 5/9
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OpenStudy (anonymous):
1 is wrong
OpenStudy (anonymous):
3/216?
OpenStudy (anonymous):
now i dont knw about th 1 one
OpenStudy (anonymous):
oops 91/216
mathslover (mathslover):
1. What is the prob of 4 not appearing at all ?
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OpenStudy (anonymous):
tell me the answer of part 2
mathslover (mathslover):
If you only want ans. then
(1) P = \( 1 - \cfrac{5^3}{6^3}\)
mathslover (mathslover):
(2) P = \(\cfrac{6*5*4}{6^3}\) = \(\cfrac{20}{36}\)= \(\cfrac{15}{18}\)
OpenStudy (anonymous):
yeah its ryt
91/216
mathslover (mathslover):
Well why do you want only answers ?
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OpenStudy (anonymous):
i didnt mean that
first explain me
then tell me how to solve it