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OpenStudy (anonymous):

A die is a six-sided figure; each side shows a number of spots; the numbers of spots on the six sides are 1, 2, 3, 4, 5, and 6. Unless the problem says otherwise, you can assume that the die is fair, that is, each face has chance 1/6 of appearing regardless of what has appeared before. 1.A die is rolled three times. Find the chance that the face with 4 spots appears at least once. 2.A die is rolled three times. Find the chance that three different faces appear.

OpenStudy (anonymous):

i believe it is 3/18 and 15/18. not sure though.

OpenStudy (anonymous):

no its wrong

OpenStudy (anonymous):

Do you have answer choices?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

1. 31/216 2. 5/9

OpenStudy (anonymous):

1 is wrong

OpenStudy (anonymous):

3/216?

OpenStudy (anonymous):

now i dont knw about th 1 one

OpenStudy (anonymous):

oops 91/216

mathslover (mathslover):

1. What is the prob of 4 not appearing at all ?

OpenStudy (anonymous):

tell me the answer of part 2

mathslover (mathslover):

If you only want ans. then (1) P = \( 1 - \cfrac{5^3}{6^3}\)

mathslover (mathslover):

(2) P = \(\cfrac{6*5*4}{6^3}\) = \(\cfrac{20}{36}\)= \(\cfrac{15}{18}\)

OpenStudy (anonymous):

yeah its ryt 91/216

mathslover (mathslover):

Well why do you want only answers ?

OpenStudy (anonymous):

i didnt mean that first explain me then tell me how to solve it

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