I need help with 64
What's the bar over B'C' mean?
It does not mean anything. I just need the answer.
Just do it how it is, don't worry about the bar please.
Do you see that the triangles are congruent?
Yes
>> What's the bar over B'C' mean? Segment is what the bar means.
Then to find B'C', all you have to do is look at the other one.
So what would be my answer, or how do I set up the work?
@Directrix, is that as opposed to the little angle marks I sometimes see on these problems?
The question is "the length of B'C'" It's a number. That number is your answer.
I don't get it. Can you write it down please on here and show me?
Look...what's the length of BC?
>> little angle marks Give me an example of a little angle mark. Back on that bar thing, segment B'C' is read as: segment B prime C prime. Those primes indicate that point B' corresponds to point B in the other similar polygon. It's a cool way to indicate corresponding vertices.
It's 11
Correct. And what's the definition of congruency?
Same
So wait my answer is 11?
Correct again. So if BC is 11, then what is B'C'?
Do I divide or multiply?
You don't need to do anything fancy, it's just plain old "11". BC = B'C' B'C' = BC
So it would also be 11?
YES!!!!!
Overall 11 is my answer
The answer to #64 is 11
The quadrilaterals are congruent so corresponding sides, by definition of congruent polygons, would be congruent. Wow, I read "congruent" as similar. Of course, congruence is a special case of similarity when the ratio of corresponding sides is one to one.
And thanks, @Directrix for the "bar" info. It's kind of confusing because when I see 2 plane figures like that and know they're congruent, when I see B'C' I automatically assume BC, so the bar seems kind of superfluous. :-)
Well, BC alone could mean so many things. As is, BC is defined to be the length of segment BC. So, segment BC is a set of points whereas BC is a real number. Then, there is ray BC, line BC, blah, blah,blah. The "hat" BC wears is significant. @sid28
@qweqwe123123123123111 ^^^^ I mistakenly pinged @sid28
One of these days I ought to actually sign up for one of these courses just to learn the finer points like these... :-)
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