Question

vector problem..
I will give medal

Answer 1

Can somebody please tell me how to do question 2b, e and f? Thank you!

Answer 2

a vector can be scaled to any length for 2b

Answer 3

could you please explain why?

Answer 4

prolly not. some things are just too basic for me to break down further.

Answer 5

it has to do with linear properties and similar triangles

Answer 6

I think I understand what you are trying to say
Could you please tell me how to do question 2e and f as well?

Answer 7

the same underlying principle applies to how we are able to add and subtract vectors

Answer 8

adding vectors can be thought of as placing the vectors end to end and the result is a vector from the start to the end of it

Answer 9

* a+CQ=BQ

Answer 10

in terms of CQ, we had to flip it around to point from Q to C

Answer 11

Sorry I don't get it

Answer 12

The question says CQ @@

Answer 13

the vector for C to Q is going in the wrong direction

if we start at B and go to Q, we define the vector BQ

to to get to C from there, in terms of the vector CQ, we need to reverse the vector to go in the other direction from which it is pointing.

-CQ is the same as saying, QC

BQ + QC = BC
BQ - CQ = BC

is all it amounts to

Answer 14

not real sure how to approach "f" tho

Answer 15

oh, part d gives a second setup to determine BC (or a with)

Answer 16

I think part d has nothing to do with e @@

Answer 17

PN = 1/2 BC

PN = PQ+QN

PN = -QP+QN = 1/2 a

Answer 18

do you equate PN=1/2 BC then?

Answer 19

yes, since 1/2 a = 1/2 BC

so, we know that

a = 2QN - 2QP
a = BQ - QC

Answer 20

a = 2QN - 2QP
a = BQ - CQ <-- had my C and Q backwards :)

Answer 21

then what can we do?

Answer 22

since QP = \(\alpha\)CQ
and -2QP = -1CQ; \(\alpha=1/2\)

Answer 23

same principle for determining \(\beta\)

Answer 24

Thank you very much for your help =]

Answer 25

good luck ;)