Help me solve: A table for y = x^2 - 25 is given below. Solve each equation or inequality. x = -6, -5, -1, 0, 1, 5, 6 y = 11, 0, -24, -25, -24, 0, 11 a.) x^2 - 25 = 0 b.) x^2 - 25 < 0 c.) x^2 - 25 > 0
Difference of squares, a stock equation, is what Luis popped in with, which is a good thing to remember!
Take any two squares, like the \(x^2\) and \(b^2\) that he used, and their difference is always going to come out like that. \(x^2-b^2=(x-b)(x+b)\)
Use difference of squares:\[(x^2-y^2)=(x-y)(x+y) \implies x^2-25 = (x-..)(x+..)\]Can you tell us what the expression turns in to now? @angelina22309
Am I just suppose to plug in one of the x values it gives me?
So what part of this one was giving you trouble?
Ah, so they do not tell you what needs to be done in this one?
Solve each equation or inequality
AH. OK. Also, look at b and c, you put them in as the same.
OK. So we have a), the \(x=\{-5,5\}\) and \(y=0\). At this point, I think this is asking you to account for al the numbers below, but not 100% sure. However, from finding that first thing you can work towards the others.
I updated the question @e.mccormick
OK. this looks like they want you to make it into a set of equations for when one thing or another is true.
|dw:1365978636379:dw| Does this make sense? @angelina22309
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