how do i find the oblique asymptote of i(x)= 8x^3-10x^2-7x-1/2x^2-3x-1

Question

agent0smith · Answer

Be careful to post equations like this without parentheses... guessing it's $$\Large i(x) = \frac{ 8x^3-10x^2-7x-1 }{ 2x^2-3x-1 }   $$

You probably want to start with polynomial long division, or synthetic division (but it doesn't look like the denominator will factor).

anonymous · Answer

yes im sorry about that, im in a rush to get this worksheet done but i am struggling with this problem

mertsj · Answer

Use long division.  Divide the numerator by the denominator.  If there is a remainder, discard it.  The oblique asymptote will be y = whatever you get for the quotient.

anonymous · Answer

can you show me?

anonymous · Answer

im not familiar with long division

anonymous · Answer

is 4x+11 correct?

mertsj · Answer

https://www.wolframalpha.com/input/?i=%288x^3-10x^2-7x-1%29%2F%282x^2-3x-1%29

anonymous · Answer

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Therefore, your oblique asymptote is y=4x+1