Question

find an equation at the tangent line to the curve y=e^x/(1+x^2) at the point (1,e/2).

Answer 1

you differerentiate the curive first for the tangent of the line..then plug in \(x\) for the gradient..

show me your work first.

Answer 2

y=e^x/(1+x^2)
f'(x)=1+x^2(1)-e^x(x)/(1+x^2)^2
f'(1)=1+(1)^2-e^1/1+((1)^2)^2
f'(1)=2-e^1/4

Answer 3

i don't no whether this is correct or incorrect.please can i have the answer please

Answer 4

You stuffed up the numerator when differentiating the curve/function.

Answer 5

You didn't do the quotient rule properly in the numerator.