Question

Trigo help
Solve for X.

Answer 1

\[\LARGE \sin^{-1}x+\cos^{-1}2x=\frac{\pi}{6}\]

Answer 2

I tried..2 ways

Answer 3

\[\LARGE \sin^{-1}(x \times \sqrt{1-\sqrt{1-4x^2}}+\sqrt{1-4x^2} \times \sqrt{1-x^2})\]

Answer 4

@ParthKohli @shubhamsrg

Answer 5

Remember one thing: NEVER CALL PARTHKOHLI FOR TRIG

Answer 6

:/

Answer 7

parth ko nhi aata to mereko na aana koi badi baat nhi hai. #parthmaharajkijai

Answer 8

dance karte hai nahi ata to :/

Answer 9

lets dance @DLS @yrelhan4 @ParthKohli hammein bass time pass hi to karnein aa taa h!!!! right guys!!!

Answer 10

right

Answer 11

@uri will help!! :O

Answer 12

so in which song we all dance??

Answer 13

http://www.youtube.com/watch?v=9bZkp7q19f0

Answer 14

x=1/2

Answer 15

I know but I don't know how to do it,it i s obvious from question

Answer 16

sorry dude, not sure, I graphed it and it hit x axis at x= half

Answer 17

if it helps:
cos^-1 (2x) = 1/2 (pi - 2 (sin^-1 (2x) )
so:
sin^-1 (x) + cos^-1 (2x) = pi/6
sin^-1 (x) + 1/2 (pi - 2 (sin^-1 (2x) ) = pi/6
sin^-1 (x) - sin^-1 (2x) = -pi/3

Answer 18

@hartnn

Answer 19

i have a pretty long method, but getting a answer.
i put x= sin y

y+arccos (2sin y) = pi/6
on simplification gives
tan y = 1/ sqrt 3
so i am getting a value for 'x' , donno whether the metod is correct

Answer 20

do you have answer ? is x=1/2 ?

Answer 21

yes!

Answer 22

i got x=1/2 from my method i mentioned

Answer 23

did you get my method ?

Answer 24

this is an easy question,
just take sine ion both sides -_-

Answer 25

on* both sides*

Answer 26

ions !!