Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

The assumption that is a perpendicular bisector of is not enough to show that YXZ YAZ.

OpenStudy (anonymous):

|dw:1366033128305:dw|

OpenStudy (anonymous):

A. True B. False

terenzreignz (terenzreignz):

the assumption that (?) is a perpendicular bisector?

OpenStudy (anonymous):

The assumption that YZ is a perpendicular bisector of AX is not enough to show that YXZ YAZ.

OpenStudy (anonymous):

Confused, but XZ=ZA If it is a biscetor. Then the right angles are same. and the side in the middle is same by Reflexive prop. So triangles would be equal by SAS

OpenStudy (anonymous):

So explain on how i would know the answer

OpenStudy (anonymous):

So IF it is a Bisector you could prove the triangles equal. Correct?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

So do you need proving steps to show it?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Can I assume the bottom line is equally split?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Then line XZ=ZA Because it is being split into two equal lines.

OpenStudy (anonymous):

Also, a perpendicular ALWAYS makes right angles, so there are two right angles made there.

OpenStudy (anonymous):

Then YZ=ZY by the Reflexive Property. (AKA, YZ is the same as itself.)

OpenStudy (anonymous):

So you can preove the two triangles congruent by the SAS: Side Angle Side

OpenStudy (anonymous):

So, False. You can prove it, If you are to assume the perpendicular bisector is true then you can prove the triangles equal.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!