Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

select the system of equations that corresponds to the given graph. graph below!!!!!!! please help

OpenStudy (anonymous):

OpenStudy (anonymous):

@touseii45

OpenStudy (anonymous):

@shorite14

OpenStudy (anonymous):

Well basically what you want to do is find the slope of each of the lines and you have your system of equations, they will be in slope intercept form i believe

OpenStudy (anonymous):

do you know how to do that?

OpenStudy (anonymous):

i got 2x + 2y = 12 4x +2y = 4

OpenStudy (anonymous):

is that right or did i make a mistake?

OpenStudy (anonymous):

uhm well im not sure cause i havent done this for a while so i dont remember but maybe @electrokid can help you

OpenStudy (anonymous):

is he online?

OpenStudy (anonymous):

yea he is

OpenStudy (anonymous):

@Mertsj @UnkleRhaukus

OpenStudy (anonymous):

Maybe they can help(:

OpenStudy (anonymous):

okat :)

OpenStudy (unklerhaukus):

when you solve the correct system you should get (x,y) = (0,3)

OpenStudy (anonymous):

so am i right? @UnkleRhaukus

OpenStudy (anonymous):

the graph of a system of parallel lines will intersect exactly 1 point. always sometimes never @touseii45

OpenStudy (anonymous):

|dw:1366038379678:dw| by this what do you think the answer is?

OpenStudy (anonymous):

never

OpenStudy (anonymous):

Correct(:

OpenStudy (anonymous):

you are looking for the equations of the two lines.. 1) get their slopes

OpenStudy (anonymous):

how @electrokid

OpenStudy (anonymous):

|dw:1366038726931:dw| \[{\rm slope} = {y_2-y_1\over x_2-x_1}={0-3\over 6-0}=-{1\over2}\] then equation of line: \[y=mx+b\\y={-1\over2}x+3\] where b = y-intercept = 3 for both the lines

OpenStudy (anonymous):

that is one of the lines.. similarly, get the second line slope. it has the same y-intercept

OpenStudy (anonymous):

|dw:1366038898799:dw|

OpenStudy (anonymous):

@allie_bear22 you follow?

OpenStudy (anonymous):

(0.3) is were they all come together

OpenStudy (anonymous):

yes. but the question you've put up asks for the equations of the two lines. I just showed you one of the two lines. similarly, get the equation of the second one.

OpenStudy (anonymous):

(0,6)

OpenStudy (anonymous):

that is a point on the line.... we are done with that line.... |dw:1366039149014:dw|

OpenStudy (anonymous):

OpenStudy (anonymous):

(3,1)

OpenStudy (anonymous):

you have to try.. not guess

OpenStudy (anonymous):

how did you get 2x+2y=12 ?

OpenStudy (anonymous):

this is what i got for an answer 4x + 2y =12 4x +2y =4

OpenStudy (anonymous):

was that the first option??? and if it was wrong somebody would give away the answer?

OpenStudy (anonymous):

and you keep trying the four options?

OpenStudy (anonymous):

wow really?! no i really thought thats what it was

OpenStudy (anonymous):

so stop accusing me okay

OpenStudy (anonymous):

dont "think". math does not ask thinking.. it asks for "following the steps"

OpenStudy (anonymous):

your supposed to be help not treating people like there stupid so get it together

OpenStudy (anonymous):

I am not. I asked you how you got that answer and you never answered that

OpenStudy (anonymous):

How am I supposed to know what went wrong in your work and help you if you do not show me what you did!!!?

OpenStudy (anonymous):

@allie_bear22 He is just trying to help, he isnt accusing you of anything

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!