Ask your own question, for FREE!
Biology 13 Online
OpenStudy (anonymous):

Over which interval is the velocity greatest?

OpenStudy (anonymous):

OpenStudy (anonymous):

i looooooove one direction<3

OpenStudy (anonymous):

haha sorry for trollin

OpenStudy (anonymous):

vl=displacemnt/time.....so u count squares for dis and divide it by time squares...for each straight line of graph which is changig will give the answer.

OpenStudy (anonymous):

@qweqwe123123123123111 @WeNeedDaAnswas @EmoLover3 @ex @Tomas.A @telijahmed @iluvreading @Opcode @poopsiedoodle @Preetha @agreene @anas2000 @Algebra1Flunk @AnElephant @supercrazy92 @Sean_Le_Van @Sarah_Miller720 @studmuffin @shortielynn @silly_girl124 @divagirl421 @Frostbite @FlaCaLOL @frogs29 @faithelizabeth

OpenStudy (anonymous):

why did u call so many people

OpenStudy (anonymous):

cause half of them dont come

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

il try to help

OpenStudy (anonymous):

yah so i figured the more the better cause someone might know how to help

OpenStudy (anonymous):

what grade u in

OpenStudy (anonymous):

welll 8th but that doesnt have to do with the question

OpenStudy (anonymous):

im and 7th and i dont understand da question

OpenStudy (anonymous):

velocity = displacement/time or in this case v=d/t where d is the distance therefore, the time with the biggest slope should be the greatest velocity which is (0,3) Correct me if I'm wrong for any reason...

OpenStudy (anonymous):

*time interval

OpenStudy (anonymous):

is the biggest slope a

OpenStudy (anonymous):

it's A->B I'm not sure if A is pointing at the 0 mark or the line segment...

OpenStudy (anonymous):

hmm yah i see what your getting at

OpenStudy (anonymous):

A:B is the greatest acceleration. However, I see C:D as having the greatest velocity of 6m/s over 8 seconds.

OpenStudy (anonymous):

well its asking for the greatest velocity so would that be c d

OpenStudy (anonymous):

Yup! That's what I would mark, :-)

OpenStudy (anonymous):

Clarification question: Does that graph show the distance from a fixed point of an object?

OpenStudy (anonymous):

ok thank you could you ehlp em with a couple other questions using the same graph

OpenStudy (anonymous):

if u know what velocity means u will get the answer

OpenStudy (anonymous):

well my question if you want ot help is over which interval is the velocity zero

OpenStudy (anonymous):

I see no interval where the velocity is zero.

OpenStudy (anonymous):

thats why im confused

OpenStudy (anonymous):

Confused about what?

OpenStudy (agreene):

\[\vec{v} = \frac{\vec{r}}{t}\] I dont understand what your not understanding.

OpenStudy (anonymous):

cause i see no interval fo zero so i dont know what to answer it as

OpenStudy (anonymous):

Can you show us a source for the questions you're asking?

OpenStudy (agreene):

if \[|\vec{r}| = 0 \implies |\vec{v}| = 0\] so look for where the graph is flat to find sections of 0 velocity.

OpenStudy (anonymous):

its just that graph and this question so yah

OpenStudy (anonymous):

A flat line would indicate 0 acceleration, not zero velocity.

OpenStudy (anonymous):

its probably c - d because its the only thing that doesnt increase or decrease

OpenStudy (anonymous):

I thought the flat line indicates no change in any rate so the displacement would be 0 right? or is that wrong?

OpenStudy (anonymous):

Is this a multiple choice question?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

its a blank that u fill in

OpenStudy (anonymous):

True enough, @AnElephant. The flat line in the graph is maintaining a speed of 6m/s for 8 seconds - and that is a "velocity". Zero distance over time is zero velocity, and their are no segments that show zero distance.

OpenStudy (anonymous):

ah nevermind then, i thought the graph showed the particle or whatever staying at a constant distance of 6 for however many seconds there were

OpenStudy (anonymous):

Well, I'm not enrolled in any of these courses so I can't speak with authority, but *IF* I were, and IF I had this question, I would fill in that there are no segments showing zero velocity.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!