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Evaluate the integral using integration by parts where possible (2-x)e^x dx
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Notice that our \(2-x\), if differentiated, will reduce to a constant; our \(e^x\), however, will not. This means we should should treat our integral as (by integration by parts): \(\int(2-x)\,\mathrm{d}(e^x)=(2-x)e^x-\int e^xd(2-x)\)
so I dont need to worry about the (2-x)?
\[\int (2-x)e^x dx=2\int e^xdx -\int xe^xdx\] is a start
first part is pretty obviously \(2e^x\) it is the second integral \[\int xe^xdx\] that requires parts
you know how to do that?
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is it uv-vdu?
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