Algebra help please! (see details)

Question

anonymous · Answer

$$7 - 3[(n ^{3} + 8n) ÷ (-n) + 9n ^{2}]$$

anonymous · Answer

$$I solved like this... (above equation) then
-n ^{2} - 8n + 9n$$
$$8n ^{2} -8n$$
$$-27n ^{2} + 28n + 7$$

anonymous · Answer

i know the basic principals, but the way i solved it wrong, could you walk me through the steps?

blurbendy · Answer

I set it up a different way.

First, simplify (n^3 + 8n / (n)

= n^3 / n + 8n / n

= n^2 + 8

follow?

blurbendy · Answer

( -n) sorry

anonymous · Answer

ok so that would be -n^2 -8n

anonymous · Answer

so i did the math..
n^2 - 8n + 9n^2
7n^2 - 8n
-21n^2 + 24n + 7
correct?

blurbendy · Answer

it would not be -8n, just -8 because the n's would cancel out

blurbendy · Answer

so you have 7 - 3(-n^2 -8 + 9n^2)

The next step would be to distribute the 3

anonymous · Answer

3^2 + 24 -27n^2 + 7
-14n^2 + 31

blurbendy · Answer

that should be 3n^2 which you can add to -27n^2 to get 31 - 24n^2

anonymous · Answer

oh oops thanks for pointing that out! ok so then that is -24n^2 + 31 as the answer

blurbendy · Answer

did the question ask to simplify or solve for n?

anonymous · Answer

just simplify. thank you for your help =)

blurbendy · Answer

np!