Question

Please can You help!
A person is selected at random from a population that has the following characteristics are as follow:
30% of the people are women; the others are men (70%)

9% of the women are alcoholic
2% of the men are alcoholic
i-)Find the probability that the selected person is a non-alcoholic, given that the person is a women.
ii-)Find the probability that the selected person is a men who is alcoholic.

Answer 1

Show your work first so that others can know where to offer a help from and also avoid repeating what you have already known.

Answer 2

P(non-alcoholic)=1-p%w

Answer 3

P(non-alcoholic)=1- (.3*.91)

Answer 4

Pw(non-alcoholic)=1-(.3*.91)..?

Answer 5

Given that the person is a women, what is the probability that she is alcoholic? (The answer lies inside the problem.)

Answer 6

P(W-alcoholic)= .30*.09=2.7% so i) p(W-nonalcoholic)=30%-2.7%=27.3%

Answer 7

No, not that way. Stare at this sentence : '9% of the women are alcoholic'. Do you know what it means?

Answer 8

no explain?9%

Answer 9

Well it means given that a person is a woman, the chance that she is alcoholic is 9%. Think about it.

Answer 10

i)Therefore the chance the remaining women chance P(w non alcoholic) is 100%-9%=91%

Answer 11

great, how about (ii)?

Answer 12

correction the women population 30%-9%=21%

Answer 13

what is the 30% is it extra info

Answer 14

Nope, the previous answer is correct. 'Given that', so just forget what the population of the women is

Answer 15

Nope, it's used to calculate part(ii)

Answer 16

thanks! drawar for clarifying!

Answer 17

next-ii)

Answer 18

ii) P(M alcoholic)=2%

Answer 19

No, it would be the correct answer if the question asks you to find the probability that the selected person is an alcoholic, GIVEN THAT the person is a man.

Answer 20

how do you approach do you quantify the women in i as a chance effecting the men with the fact 2% of m2n alcoholic or I calculate like women above man independent from women?

Answer 21

ii) P(M alcoholic)=100%-2%=98%

Answer 22

No, use the product rule for (ii)

Answer 23

ii) Product rule P(A and B)= P(A)*P(B)=2%*70%=.02*0.7=1.4%

Answer 24

correct!

Answer 25

thanks! can you check setup this one
A poker hand (5 cards) is dealt. i Find the chance that the cards are all diamond.

Answer 26

can you help me check this one:
i)P(all diamond)= (13/52)*(12/51)*(11/50)*(10/49)*(9/48)

Answer 27

Correct!